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प्रश्न
Trapezium given below; find its area.
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उत्तर
In ΔCMB
CB2 = CM2 + MB2
(10)2 = CM2 + (6)2
100 - 36 = CM2
`sqrt64` = CM
CM = 8 cm
Area of ABCD = `1/2 xx ( 8 + 14 ) xx 8`
= 22 × 4
= 88 cm2
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