Advertisements
Advertisements
प्रश्न
The rate for a 1.20 m wide carpet is Rs. 40 per meter; find the cost of covering a hall 45 m long and 32 m wide with this carpet. Also, find the cost of carpeting the same hall if the carpet, 80 wide, is at Rs. 25. Per meter.
Advertisements
उत्तर
First, we have to calculate the area of the hall.
Area = 45 x 32
= 1440 m2
Cost = `40/1.20 xx 1440`
= 48,000
We need to find the cost of carpeting of 80 cm = 0.8 m wide carpet if the rate of carpeting is Rs. 25. Per meter.
Then
Cost = `25/0.8 xx 1440`
= Rs. 45,000
APPEARS IN
संबंधित प्रश्न
Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.

The diagonal of a rectangular plot is 34 m and its perimeter is 92 m. Find its area.
A rectangular plot 85 m long and 60 m broad is to be covered with grass leaving 5 m all around. Find the area to be laid with grass.
A footpath of uniform width runs all around the outside of a rectangular field 30 m long and 24 m wide. If the path occupies an area of 360 m2, find its width.
The figure given below shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 cm, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.

Find the area and perimeter of a square plot of land, the length of whose diagonal is 15 meters. Given your answer correct to 2 places of decimals.
Using the information in the following figure, find its area.
Find the area of the quadrilateral whose vertices are at (– 9, 0), (– 8, 6), (– 1, – 2) and (– 6, – 3)
The quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio
If vertices of a quadrilateral are at A(– 5, 7), B(– 4, k), C(– 1, – 6) and D(4, 5) and its area is 72 sq. units. Find the value of k.
