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The Vertices of a Quadrilateral Are a (−2, 6), B (1, 2), C (10, 4) and D (7, 8). Find the Equation of Its Diagonals. - Mathematics

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प्रश्न

The vertices of a quadrilateral are A (−2, 6), B (1, 2), C (10, 4) and D (7, 8). Find the equation of its diagonals.

थोडक्यात उत्तर
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उत्तर

The two diagonals of the quadrilateral with vertices A (−2, 6), B (1, 2), C (10, 4) and D (7, 8) are ACand BD.
The equation of AC passing through A (−2, 6) and C (10, 4) is

\[y - 6 = \frac{4 - 6}{10 + 2}\left( x + 2 \right)\]

\[ \Rightarrow x + 6y - 34 = 0\]

And, the equation of BD passing through B (1, 2) and D (7, 8) is

\[y - 2 = \frac{8 - 2}{7 - 1}\left( x - 1 \right)\]

\[ \Rightarrow x - y + 1 = 0\]

Hence, the equations of the diagonals are \[x + 6y - 34 = 0\] and \[x - y + 1 = 0\].

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Equation of a Straight Line - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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पाठ 23: The straight lines - Exercise 23.5 [पृष्ठ ३५]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 23 The straight lines
Exercise 23.5 | Q 10 | पृष्ठ ३५

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