Advertisements
Advertisements
प्रश्न
The value of cosec(70° + θ) – sec(20° − θ) + tan(65° + θ) – cot(25° − θ) is
पर्याय
0
1
2
3
Advertisements
उत्तर
0
Explanation;
Hint:
cosec(70° + θ) – sec(20° – θ) + tan(65° + θ) – cot(25° – θ)
= sec[90° – (70° + θ)] – sec(20° – θ) + tan(65° + θ) – tan[90° – (25° – θ)]
= sec(20° – θ) – sec(20° – θ) + tan(65° + θ) – tan(65° + θ)
= 0
APPEARS IN
संबंधित प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0º and 45º;
(i) cosec 69º + cot 69º
(ii) sin 81º + tan 81º
(iii) sin 72º + cot 72º
Prove the following trigonometric identities.
(secθ + cosθ) (secθ − cosθ) = tan2θ + sin2θ
Use tables to find the acute angle θ, if the value of sin θ is 0.3827
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
The value of tan 10° tan 15° tan 75° tan 80° is
A, B and C are interior angles of a triangle ABC. Show that
sin `(("B"+"C")/2) = cos "A"/2`
Express the following in term of angles between 0° and 45° :
cosec 68° + cot 72°
The value of the expression (cos2 23° – sin2 67°) is positive.
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
