Advertisements
Advertisements
प्रश्न
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Advertisements
उत्तर
cos x = cos 60° cos 30° – sin 60° sin 30°
cos x = `(1/2)(sqrt3/2) - (sqrt3/2)(1/2)`
cos x = 0 = cos 90°
Hence, x = 90°
APPEARS IN
संबंधित प्रश्न
If `tan theta = 12/5` find the value of `(1 + sin theta)/(1 -sin theta)`
Prove that:
`1/(1 + sin(90^@ - A)) + 1/(1 - sin(90^@ - A)) = 2sec^2(90^@ - A)`
If \[\tan \theta = \frac{4}{5}\] find the value of \[\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta}\]
If A + B = 90°, then \[\frac{\tan A \tan B + \tan A \cot B}{\sin A \sec B} - \frac{\sin^2 B}{\cos^2 A}\]
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
A, B and C are interior angles of a triangle ABC. Show that
sin `(("B"+"C")/2) = cos "A"/2`
A, B and C are interior angles of a triangle ABC. Show that
If ∠A = 90°, then find the value of tan`(("B+C")/2)`
The value of tan 72° tan 18° is
Prove that `(tan A)/(cot A) = (sec^2A)/("cosec"^2A)`.
The value of the expression (cos2 23° – sin2 67°) is positive.
