Advertisements
Advertisements
प्रश्न
The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate: Heat capacity of lead piece.
Advertisements
उत्तर
Heat capacity of lead piece
= `"Heat supplied"/"Rise in temperature" = (1560 "J")/(50 - 20^circ "C")` = 52 J/° C.
संबंधित प्रश्न
Calculate the mass of ice required to lower the temperature of 300 g of water 40°C to water at 0°C.
(Specific latent heat of ice = 336 J/g, the Specific heat capacity of water = 4.2J/g°C)
Name the S.I. unit of heat.
Why do the farmers fill their fields with water on a cold winter night?
Water property of water makes it an effective coolant?
State, with reason, which of the two, boiling water or steam both at 100°C will produce more severe burns.
What are other units of heat? Name and define them.
State the condition for the flow of heat energy from one body to another.
Does the specific heat capacity of a substance depend upon its mass and rise in temperature only?
Explain, why is water sprayed on roads in evening in hot summer?
Answer the following question.
Why do we generally consider two specific heats of a gas?
