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प्रश्न
The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate: Heat capacity of lead piece.
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उत्तर
Heat capacity of lead piece
= `"Heat supplied"/"Rise in temperature" = (1560 "J")/(50 - 20^circ "C")` = 52 J/° C.
संबंधित प्रश्न
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