Advertisements
Advertisements
प्रश्न
The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.
Advertisements
उत्तर
Moment of force = 2.5 N m
Force applied = 25
⊥ distance from the point of rotation?
Moment of force = Force × ⊥ distance
2.5 = 25 × χ
∴ x = ⊥ distance = `2.5/25 = 1/10` m
= `1/10` × 100
= 10 cm
APPEARS IN
संबंधित प्रश्न
A nut is opened by a wrench of length 20 cm. If the least force required is 2N, find the moment of force needed to loosen the nut.
A potter turns his wheel by applying a force through the stick near the rim of wheel.
The stone of hand flour grinder is provided with a handle near its rim. Give reason.
Classify the following amongst contact and non-contact forces.
normal reaction force,
Give an example for each of the following uses of a machine:
to change the point of application of force
In a beam balance when the beam is balanced in a horizontal position, it is in ________ equilibrium.
What is meant by the term ‘moment of force’? If the moment of force is assigned a negative sign then will the turning tendency of the force be clockwise or anti-clockwise?
Calculate the length of arm of couple, if a force of 13 N produces a moment of couple of 14.3 Nm.
A person standing in front of a cliff fires a gun and hears its echo after 3 s. If the speed of sound in air is 336 ms−1.
- Calculate the distance of the person from the cliff.
- After moving a certain distance from the cliff, he fires the gun again, and this time the echo is heard 1.5 s later than the first. Calculate the distance that the person moved.
A nut is opened by a wrench of length 25 cm. If the least force required is 10 N, find the moment of force needed to turn the nut.
