मराठी

The line segment joining points (−3, −4), and (1, −2) is divided by y-axis in the ratio. - Mathematics

Advertisements
Advertisements

प्रश्न

The line segment joining points (−3, −4), and (1, −2) is divided by y-axis in the ratio. 

पर्याय

  • 1 : 3

  •  2 : 3

  • 3 : 1

  • 2 : 3

MCQ
Advertisements

उत्तर

3 : 1

Explanation: 

Let P(0, y)  be the point of intersection of y-axis with the line segment joining A (−3,−4) and B (1, −2) which divides the line segment AB in the ratio λ : 1.

Now according to the section formula if point a point P divides a line segment joining` A (x_1, y_1)  "and"  B  (x_2, y_2)` in the ratio m : n internally than,

`P(x , y ) = ((nx_1+mx_2)/(m+n) , (ny_1+my_2)/(m+n))`

Now we will use section formula as,

`(0 , y) = ((lambda -3)/(lambda + 1) , (-2lambda -4)/(lambda+1))`

Now equate the x component on both the sides,

`(lambda - 3 ) /(lambda +1) = 0`

On further simplification,

`lambda = 3`

So y-axis divides AB in the ratio `3/1`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Co-Ordinate Geometry - Exercise 6.7 [पृष्ठ ६४]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 6 Co-Ordinate Geometry
Exercise 6.7 | Q 20 | पृष्ठ ६४

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

On which axis do the following points lie?

S(0,5)


Prove that the points (−2, 5), (0, 1) and (2, −3)  are collinear.


Find the value of k, if the point P (0, 2) is equidistant from (3, k) and (k, 5).


In Fig. 14.36, a right triangle BOA is given C is the mid-point of the hypotenuse AB. Show that it is equidistant from the vertices O, A  and B. 

    

We have a right angled triangle,`triangle BOA`  right angled at O. Co-ordinates are B (0,2b); A (2a0) and C (0, 0).

 

 

 


Find a point on y-axis which is equidistant from the points (5, -2) and (-3, 2).


If the coordinates of the mid-points of the sides of a triangle be (3, -2), (-3, 1) and (4, -3), then find the coordinates of its vertices.


Find the coordinates of the points which divide the line segment joining the points (-4, 0) and (0, 6) in four equal parts.


Points P, Q, R and S divide the line segment joining the points A(1,2) and B(6,7) in five equal parts. Find the coordinates of the points P,Q and R


The base BC of an equilateral triangle ABC lies on y-axis. The coordinates of point C are (0, −3). The origin is the midpoint of the base. Find the coordinates of the points A and B. Also, find the coordinates of another point D such that ABCD is a rhombus.


In what ratio does the point C (4,5) divides the join of A (2,3)  and B (7,8) ?


Point P(x, 4) lies on the line segment joining the points A(−5, 8) and B(4, −10). Find the ratio in which point P divides the line segment AB. Also find the value of x.


If the point P (m, 3) lies on the line segment joining the points \[A\left( - \frac{2}{5}, 6 \right)\] and B (2, 8), find the value of m.

 
 

What is the distance between the points  \[A\left( \sin\theta - \cos\theta, 0 \right)\] and \[B\left( 0, \sin\theta + \cos\theta \right)\] ?

 
 

If A (5, 3), B (11, −5) and P (12, y) are the vertices of a right triangle right angled at P, then y=


The area of the triangle formed by (ab + c), (bc + a) and (ca + b)


If points A (5, pB (1, 5), C (2, 1) and D (6, 2) form a square ABCD, then p =


The ratio in which the line segment joining P (x1y1) and Q (x2, y2) is divided by x-axis is


In the above figure, seg PA, seg QB and RC are perpendicular to seg AC. From the information given in the figure, prove that: `1/x + 1/y = 1/z`


Find the point on the y-axis which is equidistant from the points (5, −2) and (−3, 2).


What are the coordinates of origin?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×