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प्रश्न
The gravitational attraction between electron and proton in a hydrogen atom is weaker than the Coulomb attraction by a factor of about 10−40. An alternative way of looking at this fact is to estimate the radius of the first Bohr orbit of a hydrogen atom if the electron and proton were bound by gravitational attraction. You will find the answer interesting.
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उत्तर
Radius of the first Bohr orbit is given by the relation,
`"r"_1 = (4pi in_0 ("h"/(2pi))^2)/("m"_"e" "e"^2)` .................(1)
Where,
∈0 = Permittivity of free space
h = Planck’s constant = 6.63 × 10−34 Js
me = Mass of an electron = 9.1 × 10−31 kg
e = Charge of an electron = 1.9 × 10−19 C
mp = Mass of a proton = 1.67 × 10−27 kg
r = Distance between the electron and the proton
Coulomb attraction between an electron and a proton is given as:
`"F"_"C" = "e"^2/(4piin_0 "r"^2)` .............(2)
Gravitational force of attraction between an electron and a proton is given as:
`"F"_"G" = ("Gm"_"p""m"_"e")/"r"^2` .........(3)
Where,
G = Gravitational constant = 6.67 × 10−11 N m2/kg2
If the electrostatic (Coulomb) force and the gravitational force between an electron and a proton are equal, then we can write:
∴ FG = FC
`("Gm"_"p""m"_"e")/"r"^2 = "e"^2/(4piin_0 "r"^2)`
∴ `"e"^2/(4piin_0) = "Gm"_"p""m"_"e"` ........(4)
Putting the value of equation (4) in equation (1), we get:
`"r"_1 = ("h"/(2pi))^2/("Gm"_"p""m"_"e"^2)`
= `(((6.63 xx 10^(-34))/(2xx3.14))^2)/(6.67 xx 10^(-11) xx 1.67 xx 10^(-27) xx (9.1 xx 10^(-31))^2) ~~ 1.21 xx 10^(29) "m"`
It is known that the universe is 156 billion light years wide or 1.5 × 1027 m wide. Hence, we can conclude that the radius of the first Bohr orbit is much greater than the estimated size of the whole universe.
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संबंधित प्रश्न
Calculate the radius of second Bohr orbit in hydrogen atom from the given data.
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Charge on the electron = 1.6 x 10-19 C
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