Advertisements
Advertisements
प्रश्न
The focal length of a convex lens is 25 cm. At what distance from the optical centre of the lens an object be placed to obtain a virtual image of twice the size?
Advertisements
उत्तर
Focal length, f = +25 cm
Image is virtual and magnified, m = +2
For a lens, magnification is
m = `v/u`
∴ + 2 = `v/u`
∴ v = 2u
Lens formula is,
`1/v = 1/u = 1/f`
∴ `1/(2u) - 1/u = 1/25`
∴ `-1/(2u) = 1/25`
∴ 2u = −25 cm
∴ u = `-25/2`
∴ u = −12.5 cm
APPEARS IN
संबंधित प्रश्न
A magnifying glass forms ______.
If the magnification produced by a lens is - 0.5, the correct statement is ______.
An object is placed at a distance of 20 cm in front of a concave lens of focal length 20 cm. find: the magnification of image.
Why is the focal length of the lens, used as a magnifying glass, kept short?
Name the lens for which magnification can be 1. For what position of the object will the magnification be 1?
Show with the help of a ray diagram, the path of the ray when incident normally on the first surface of the glass block, through the block and the liquid.
Copy and complete the following ray diagram.

An object AB is placed between 2F1 and F1 on the principal axis of a convex lens as shown in the diagram. Copy the diagram and using three rays starting from point A, obtain the image of the object formed by the lens.

(i) Draw a ray diagram to show how the lens can be used as a ‘magnifying glass’? State the nature of the lens.
(ii) In what respect does the image in (i) above different from the image formed by a concave lens?
Write an expression for the magnifying power of a simple microscope. How can it be increased?
