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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

The fission properties of ""_94^239"Pu" are very similar to those of ""_92^235 "U". The average energy released per fission is 180 MeV.

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प्रश्न

The fission properties of `""_94^239"Pu"` are very similar to those of `""_92^235 "U"`. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure `""_94^239 "Pu"` undergo fission?

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उत्तर

Average energy released per fission of `""_94^239 "Pu", "E"_"av" = 180 "MeV"`

Amount of pure `""_94"Pu"^239` m = 1 kg = 1000 g

NA= Avogadro number = 6.023 × 1023

Mass number of `""_94^239 "Pu"`= 239 g

1 mole of `""_94"Pu"^239`  contains NA atoms.

∴ mg of `""_94"Pu"^239` contain `("N"_"A"/"Mass number" xx m)` atom

`= (6.023 xx 10^23)/239 xx 1000  = 2.52 xx 10^24` atoms

∴ Total energy released during the fission of 1 kg of `""_94^239"Pu"` is calculated as:

`"E" = "E"_"av" xx 2.52 xx 10^24`

`= 180 xx 2.52 xx 10^24 = 4.536 xx 10^26` MeV

Hence, `4.536 xx 10^26` is released if all the atoms in 1 kg of pure `""_94"Pu"^239` undergo fission.

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पाठ 13: Nuclei - Exercise [पृष्ठ ४६३]

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एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 13 Nuclei
Exercise | Q 17 | पृष्ठ ४६३
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 13 Nuclei
Exercise | Q 13.17 | पृष्ठ ४६३

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