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प्रश्न
A heavy nucleus P of mass number 240 and binding energy of 7.6 MeV per nucleon splits into two nuclei Q and R of mass number 110 and 130 and binding energy per nucleon of 8.5 MeV and 8.4 MeV respectively. Calculate the energy released in fission.
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उत्तर
Total Binding Energy (BE) of P = 240 × 7.6
= 1824 MeV
Binding Energy (BE) of Q = 110 × 8.5
= 935 MeV
Binding Energy (BE) of R = 130 × 8.4
= 1092 MeV
Total Binding Energy (BE) of Q and R = (935 + 1092)
= 2027 MeV
Total energy released in the fission = 2027 − 1824
= 203 MeV
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