Advertisements
Advertisements
प्रश्न
The difference in simple interest and compound interest on a certain sum of money at \[6\frac{2}{3} %\] per annum for 3 years is Rs 46. Determine the sum.
Advertisements
उत्तर
Given:
CI - SI = 46
\[P\left[ \left( 1 + \frac{R}{100} \right)^n - 1 \right] - \frac{PRT}{100} = 46\]
\[P\left[ \left( 1 + \frac{20}{300} \right)^3 - 1 \right] - \frac{P \times 20 \times 3}{3 \times 100} = 46\]
\[\frac{4, 096}{3, 375}P - \frac{P}{5} - P = 46\]
\[\frac{(4, 096 - 3, 375 - 675)P}{3, 375} = 46\]
\[P = 46 \times \frac{3, 375}{46}\]
\[ = 3, 375\]
Thus, the required sum is Rs 3, 375 .
संबंधित प्रश्न
A certain sum amounts to Rs. 5,292 in two years and Rs. 5,556.60 in three years, interest being compounded annually. Find : the rate of interest.
The value of a machine depreciated by 10% per year during the first two years and 15% per year during the third year. Express the total depreciation of the machine, as percent, during the three years.
Calculate the difference between the compound interest and the simple interest on ₹ 7,500 in two years and at 8% per annum.
A man borrows Rs 62500 at 8% p.a., simple interest for 2 years. He immediately lends the money out at CI at the same rate and for same time. What is his gain at the end of 2 years?
Depreciation value is calculated by the formula, `"P"(1 - "r"/100)^"n"`
If the present population of a city is P and it increases at the rate of r% p.a, then the population n years ago would be `"P"(1 + "r"/100)^"n"`
The compound interest on ₹ 16000 for 9 months at 20% p.a, compounded quarterly is ₹ 2522
Find the compound interest for `2 1/2` years on ₹ 4000 at 10% p.a, if the interest is compounded yearly
The time taken for ₹ 4400 to become ₹ 4851 at 10%, compounded half yearly is _______
Suppose for the principal P, rate R% and time T, the simple interest is S and compound interest is C. Consider the possibilities.
- C > S
- C = S
- C < S
Then
