Advertisements
Advertisements
प्रश्न
The density of gold is 19 g/cm3. Find the volume of 95 g of gold.
Advertisements
उत्तर
ρ (density) = 19 g/cm3
V (volume) = ?
m (mass) = 95 g
`ρ = m/V`
`V = m/ρ`
= `95/19`
V = 5 cm3
Answer: Volume of gold = 5 cm3.
APPEARS IN
संबंधित प्रश्न
Calculate the density of an object of volume 3 m3 and mass 9 kg. State whether this object will float or sink in water. Give reason for your answer.
A piece of steel has a volume of 12 cm3, and a mass of 96 g. What is its density in g/cm3 ?
When a golf ball is lowered into a measuring cylinder containing water, the water level rises by 30 cm3 when the ball is completely submerged. If the mass of ball in air is 33 g, find its density.
An object is put in three liquids having different densities, one by one. The object floats with `1/9` , `2/11` and `3/7` parts of its volume outside the surface of liquids of densities d1, d2 and d3 respectively. Which of the following is the correct order of the densities of the three liquids?
The diagrams represent four measuring cylinders containing liquids. The mass and volume of the liquid in each cylinder are stated. Which two measuring cylinder could contain an identical liquid?
Why is it easier to swim in seawater than in river water?
Numerical Problem.
Density of mercury is 13600 kg m–3. Calculate the relative density.
Calculate the average density of the earth in terms of g, G and R
A cube of side 5 cm is immersed in water and then in a saturated salt solution. In which case will it experience a greater buoyant force. If each side of the cube is reduced to 4 cm and then immersed in water, what will be the effect on the buoyant force experienced by the cube as compared to the first case for water. Give a reason for each case.
Describe the construction and working of the Pycnometer.
