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प्रश्न
The data given below shows the production of motorbikes in a factory for some months of two consecutive years.
| Months | Feb | May | August | October | December |
| 2008 | 2700 | 3200 | 6000 | 5000 | 4200 |
| 2007 | 2800 | 4500 | 4800 | 4800 | 5200 |
Study the table given above and answer the following questions:
- Draw a double bar graph using appropriate scale to depict the above information and compare them.
- In which year was the total output the maximum?
- Find the mean production for the year 2007.
- For which month was the difference between the production for the two years the maximum?
- In which month for the year 2008, the production was the maximum?
- In which month for the year 2007, the production was the least?
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उत्तर
a. Steps to construct the bar graphs are as follows:
Step I: We draw two lines perpendicular to each other on a graph paper and call them horizontal and vertical axes.
Step II: Along the horizontal axis, OX mark the months and along the vertical axis, OY mark the production of motorbikes.
Step III: We choose a suitable scale to determine the heights of bars. Here, we choose the scale as 1 big division to represent 400.
Step IV: First, we draw the bars for Year 2008 and then bars for Year 2007 for different months.
Bars for year 2008 and year 2007 months are shaded separately and the shading is shown in the top right corner of the graph paper.
b. Total output in year 2008 = 2700 + 3200 + 6000 + 5000 + 4200 = 21100
Total output in year 2007 = 2800 + 4500 + 4800 + 4800 + 5200 = 22100
∴ Total output in year 2007 is more than year 2008.
c. Mean production for the year 2007 = `"Total production in year 2007 for 5 months"/5`
= `22100/5`
= 4420
d. It is clear from the given data in May the difference between the production for the two years in maximum, i.e. 1300.
e. In August the production was maximum, i.e. 6000 as compared to other months of year 2008.
f. In February the production was minimum, i.e. 2800 as compared to other months of year 2007.
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संबंधित प्रश्न
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