Advertisements
Advertisements
प्रश्न
The construction of a triangle ABC, given that BC = 6 cm, ∠B = 45° is not possible when difference of AB and AC is equal to ______.
पर्याय
6.9 cm
5.2 cm
5.0 cm
4.0 cm
Advertisements
उत्तर
The construction of a triangle ABC, given that BC = 6 cm, ∠B = 45° is not possible when difference of AB and AC is equal to 6.9 cm.
Explanation:
Given, BC = 6 cm and ∠B = 45°
We know that, the construction of a triangle is not possible, if sum of two sides is less than or equal to the third side of the triangle.
i.e., AB + BC < AC
⇒ BC < AC – AB
⇒ 6 < AC – AB
So, if AC – AB = 6.9 cm, then construction of ΔABC with given conditions is not possible.
APPEARS IN
संबंधित प्रश्न
Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm.
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
Construct a right-angled triangle whose perimeter is equal to 10 cm and one acute angle equal to 60°.
An angle of 52.5° can be constructed.
A triangle ABC can be constructed in which ∠B = 60°, ∠C = 45° and AB + BC + AC = 12 cm.
Construct a triangle whose sides are 3.6 cm, 3.0 cm and 4.8 cm. Bisect the smallest angle and measure each part.
Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
Construct the following and give justification:
A triangle PQR given that QR = 3 cm, ∠PQR = 45° and QP – PR = 2 cm.
Construct the following and give justification:
An equilateral triangle if its altitude is 3.2 cm.
