Advertisements
Advertisements
प्रश्न
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm
Advertisements
उत्तर
The below given steps will be followed to construct the required triangle.
Step I:- Draw line segment QR of 6 cm. At point Q, draw an angle of 60°, say ∠XQR.
Step II:- Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. (As PR > PQ and PR - PQ = 2 cm). Join SR.
Step III:- Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.
ΔPQR is the required triangle.
APPEARS IN
संबंधित प्रश्न
Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Using ruler and compasses only, construct a ΔABC, given base BC = 7cm, ∠ABC = 60° and AB + AC = 12 cm.
Using ruler and compasses only, construct a ΔABC from the following data:
AB + BC + CA = 12 cm, ∠B = 45° and ∠C = 60°.
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.
With the help of a ruler and a compass it is not possible to construct an angle of ______.
The construction of a triangle ABC, given that BC = 3 cm, ∠C = 60° is possible when difference of AB and AC is equal to ______.
Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
Construct the following and give justification:
A triangle PQR given that QR = 3 cm, ∠PQR = 45° and QP – PR = 2 cm.
Construct the following and give justification:
A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm.
