Advertisements
Advertisements
प्रश्न
Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Advertisements
उत्तर
The below given steps will be followed to construct the required triangle.
Step I:- Draw line segment AB of 12 cm. Draw a ray AX making 90° with AB.
Step II:- Cut a line segment AD of 18 cm (as the sum of the other two sides is 18) from ray AX.
Step III:- Join DB and make an angle DBY equal to ADB.
Step IV:- Let BY intersect AX at C. Join AC, BC.
ΔABC is the required triangle.
संबंधित प्रश्न
Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm.
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Construct a triangle whose perimeter is 6.4 cm, and angles at the base are 60° and 45° .
Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.
An angle of 42.5° can be constructed.
A triangle ABC can be constructed in which AB = 5 cm, ∠A = 45° and BC + AC = 5 cm.
A triangle ABC can be constructed in which BC = 6 cm, ∠C = 30° and AC – AB = 4 cm.
Construct a triangle whose sides are 3.6 cm, 3.0 cm and 4.8 cm. Bisect the smallest angle and measure each part.
Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
Construct the following and give justification:
A triangle PQR given that QR = 3 cm, ∠PQR = 45° and QP – PR = 2 cm.
