Advertisements
Advertisements
प्रश्न
Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.
Advertisements
उत्तर

Steps of construction:
Step 1: Draw a line segment BC of 6cm.
Step 2: Take midpoint D of BC.
Step 3: with center B and D and radii 6cm and 4cm draw two arcs which intersects each other A
Step 4: Join AB, AD and AC
∴ Δ ABC is the required triangle
APPEARS IN
संबंधित प्रश्न
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.
Using ruler and compasses only, construct a ΔABC from the following data:
AB + BC + CA = 12 cm, ∠B = 45° and ∠C = 60°.
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
Construct a right-angled triangle whose perimeter is equal to 10 cm and one acute angle equal to 60°.
Construct a triangle whose sides are 3.6 cm, 3.0 cm and 4.8 cm. Bisect the smallest angle and measure each part.
Construct the following and give justification:
A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm.
Construct the following and give justification:
An equilateral triangle if its altitude is 3.2 cm.
Construct the following and give justification:
A rhombus whose diagonals are 4 cm and 6 cm in lengths.
