Advertisements
Advertisements
प्रश्न
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
Advertisements
उत्तर

Steps of construction:
Step 1: Draw a line segment BC of 6cm.
Step 2: At B draw an angle le × BC of 90° .
Step 3: with center B and radius 10cm draw an arc which intersects XB at D.
Step 4: Join DC.
Step 5: Draw the perpendicular bisector of DC which intersects DB at A
Step 6: Join AC
∴ΔABC is the required triangle
APPEARS IN
संबंधित प्रश्न
Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.
Construct a ΔABC in which AB + AC = 5.6 cm, BC = 4.5 cm, AB − AC = 1.5 cm and ∠B = 45°.
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.
A triangle ABC can be constructed in which ∠B = 105°, ∠C = 90° and AB + BC + AC = 10 cm.
Construct the following and give justification:
A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm.
Construct the following and give justification:
A rhombus whose diagonals are 4 cm and 6 cm in lengths.
