Advertisements
Advertisements
प्रश्न
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
Advertisements
उत्तर

Steps of construction:
Step 1: Draw a line segment BC of 6cm.
Step 2: At B draw an angle le × BC of 90° .
Step 3: with center B and radius 10cm draw an arc which intersects XB at D.
Step 4: Join DC.
Step 5: Draw the perpendicular bisector of DC which intersects DB at A
Step 6: Join AC
∴ΔABC is the required triangle
APPEARS IN
संबंधित प्रश्न
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.
Construct a ΔABC in which AB + AC = 5.6 cm, BC = 4.5 cm, AB − AC = 1.5 cm and ∠B = 45°.
Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.
A triangle ABC can be constructed in which AB = 5 cm, ∠A = 45° and BC + AC = 5 cm.
A triangle ABC can be constructed in which BC = 6 cm, ∠C = 30° and AC – AB = 4 cm.
Construct the following and give justification:
A triangle PQR given that QR = 3 cm, ∠PQR = 45° and QP – PR = 2 cm.
Construct the following and give justification:
An equilateral triangle if its altitude is 3.2 cm.
Construct the following and give justification:
A rhombus whose diagonals are 4 cm and 6 cm in lengths.
