Advertisements
Advertisements
प्रश्न
The area of a regular hexagon of side ‘a’ is the sum of the areas of the five equilateral triangles with side a.
पर्याय
True
False
Advertisements
उत्तर
This statement is False.
Explanation:
Given: The side of a regular hexagon is ‘a’.
As we know that the regular hexagon is divided into six equilateral triangles.
So, Area of regular hexagon = Sum of area of the six equilateral triangles.
APPEARS IN
संबंधित प्रश्न
A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
Find the area of a quadrilateral ABCD is which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
The sides of a triangle are 50 cm, 78 cm and 112 cm. The smallest altitude is
If the area of an isosceles right triangle is 8 cm2, what is the perimeter of the triangle?
In the given figure, the ratio AD to DC is 3 to 2. If the area of Δ ABC is 40 cm2, what is the area of Δ BDC?
If every side of a triangle is doubled, then increase in the area of the triangle is
The adjacent sides of a parallelogram measures 34 m, 20 m and the measure of the diagonal is 42 m. Find the area of parallelogram
The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is ______.
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______.
