Advertisements
Advertisements
प्रश्न
If the area of an equilateral triangle is `16sqrt(3)` cm2, then the perimeter of the triangle is ______.
पर्याय
48 cm
24 cm
12 cm
36 cm
Advertisements
उत्तर
If the area of an equilateral triangle is `16sqrt(3)` cm2, then the perimeter of the triangle is 24 cm.
Explanation:
Given, area of an equilateral triangle = `16sqrt(3)` cm2
Area of an equilateral triangle = `sqrt(3)/4` (side)2
`sqrt(3)/4`(Side)2 = `16sqrt(3)`
⇒ (Side)2 = 64
⇒ Side = 8 cm ...[Taking positive square root because side is always positive]
Perimeter of an equilateral triangle = 3 × Side
= 3 × 8
= 24 cm
Hence, the perimeter of an equilateral triangle is 24 cm.
APPEARS IN
संबंधित प्रश्न
A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
A kite in the shape of a square with a diagonal 32 cm and an isosceles triangles of base 8 cm and sides 6 cm each is to be made of three different shades as shown in the given figure. How much paper of each shade has been used in it?

The sides of a quadrilateral, taken in order are 5, 12, 14 and 15 meters respectively, and the angle contained by the first two sides is a right angle. Find its are
Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Find the area of the trapezium.
Find the area of a quadrilateral ABCD in which AD = 24 cm, ∠BAD = 90° and BCD forms an equilateral triangle whose each side is equal to 26 cm. (Take √3 = 1.73)
Find the area of an equilateral triangle having altitude h cm.
The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its area is ______.
A park is in the shape of a quadrilateral. The sides of the park are 15 m, 20 m, 26 m and 17 m and the angle between the first two sides is a right angle. Find the area of the park
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______.
