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The Angle of Intersection of the Parabolas Y2 = 4 Ax and X2 = 4ay at the Origin is - Mathematics

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प्रश्न

The angle of intersection of the parabolas y2 = 4 ax and x2 = 4ay at the origin is ____________ .

पर्याय

  • π/6

  • π/3

  • π/2

  • π/4

MCQ
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उत्तर

π/2

 

\[\text { Given }: \]

\[ y^2 = 4ax . . . \left( 1 \right)\]

\[ x^2 = 4ay . . . \left( 2 \right)\]

\[\text { Point } =\left( 0, 0 \right)\]

\[\text { On differentiating (1) w.r.t.x,we get }\]

\[2y \frac{dy}{dx} = 4a\]

\[ \Rightarrow \frac{dy}{dx} = \frac{2a}{y}\]

\[ \Rightarrow m_1 = \infty \]

\[\text { Now, on differentiating (2) w.r.t.x, we get }\]

\[2x = 4a\frac{dy}{dx}\]

\[ \Rightarrow \frac{dy}{dx} = \frac{x}{2a} = 0\]

\[ \therefore \tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right| = \left| \frac{\infty}{1 + 0} \right| = \infty \]

\[ \Rightarrow \theta = \tan^{- 1} \infty = \frac{\pi}{2}\]

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पाठ 16: Tangents and Normals - Exercise 16.5 [पृष्ठ ४३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 16 Tangents and Normals
Exercise 16.5 | Q 22 | पृष्ठ ४३

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