मराठी

The equation of the normal to the curve y = sinx at (0, 0) is ______.

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प्रश्न

The equation of the normal to the curve y = sinx at (0, 0) is ______.

पर्याय

  • x = 0

  • y = 0

  • x + y = 0

  • x – y = 0

MCQ
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उत्तर

The equation of the normal to the curve y = sinx at (0, 0) is x + y = 0.

Explanation:

`"dy"/"dx"` = cosx.

Therefore, slope of normal = `((-1)/cosx)_(x = 0)`

= –1.

Hence the equation of normal is y – 0 = –1(x – 0) or x + y = 0

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पाठ 6: Application Of Derivatives - Solved Examples [पृष्ठ १३३]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 6 Application Of Derivatives
Solved Examples | Q 22 | पृष्ठ १३३
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