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प्रश्न
tan (90 – θ) = ?
पर्याय
sin θ
cos θ
cot θ
tan θ
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उत्तर
cot θ
Explanation:
tan(90° – θ)
= `sin(90^circ - θ)/cos(90^circ - θ)`
= `(cos θ)/(sin θ)`
= cot θ
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If cot θ = `40/9`, find the values of cosec θ and sinθ,
We have, 1 + cot2θ = cosec2θ
1 + `square` = cosec2θ
1 + `square` = cosec2θ
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`square/square` = cosec2θ ......[Taking root on the both side]
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and sin θ = `1/("cosec" θ)`
sin θ = `1/square`
∴ sin θ = `9/41`
The value is cosec θ = `41/9`, and sin θ = `9/41`
