Advertisements
Advertisements
प्रश्न
tan (90 – θ) = ?
विकल्प
sin θ
cos θ
cot θ
tan θ
Advertisements
उत्तर
cot θ
Explanation:
tan(90° – θ)
= `sin(90^circ - θ)/cos(90^circ - θ)`
= `(cos θ)/(sin θ)`
= cot θ
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities
`(1 + tan^2 theta)/(1 + cot^2 theta) = ((1 - tan theta)/(1 - cot theta))^2 = tan^2 theta`
Prove the following trigonometric identities.
`((1 + tan^2 theta)cot theta)/(cosec^2 theta) = tan theta`
Prove the following trigonometric identities.
`sqrt((1 - cos A)/(1 + cos A)) = cosec A - cot A`
Prove the following identities:
(cos A + sin A)2 + (cos A – sin A)2 = 2
Prove the following identities:
`1/(sinA + cosA) + 1/(sinA - cosA) = (2sinA)/(1 - 2cos^2A)`
If tan A = n tan B and sin A = m sin B, prove that `cos^2A = (m^2 - 1)/(n^2 - 1)`
` tan^2 theta - 1/( cos^2 theta )=-1`
`sin^6 theta + cos^6 theta =1 -3 sin^2 theta cos^2 theta`
If `cosec theta = 2x and cot theta = 2/x ," find the value of" 2 ( x^2 - 1/ (x^2))`
Prove that secθ + tanθ =`(costheta)/(1-sintheta)`.
If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2?
\[\frac{\tan \theta}{\sec \theta - 1} + \frac{\tan \theta}{\sec \theta + 1}\] is equal to
If x = a sec θ cos ϕ, y = b sec θ sin ϕ and z = c tan θ, then\[\frac{x^2}{a^2} + \frac{y^2}{b^2}\]
Prove the following identity :
secA(1 + sinA)(secA - tanA) = 1
Prove the following identities:
`(sec"A"-1)/(sec"A"+1)=(sin"A"/(1+cos"A"))^2`
If secθ + tanθ = m , secθ - tanθ = n , prove that mn = 1
Find x , if `cos(2x - 6) = cos^2 30^circ - cos^2 60^circ`
Prove that `(cosθ)/(1 + sinθ) = (1 - sinθ)/(cosθ)`.
Given that sinθ + 2cosθ = 1, then prove that 2sinθ – cosθ = 2.
Prove that `(1 + sec theta - tan theta)/(1 + sec theta + tan theta) = (1 - sin theta)/cos theta`
