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प्रश्न
If `sec theta = x ,"write the value of tan" theta`.
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उत्तर
As , `tan^2 theta = sec^2 theta -1 `
So, `tan theta = sqrt( sec^2 theta -1 ) = sqrt( x^2 -1)`
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Solution :
L.H.S. = cotθ + tanθ
= `cosθ/sinθ + sinθ/cosθ`
= `(square + square)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ............... `square`
= `1/sinθ xx 1/square`
= cosecθ × secθ
L.H.S. = R.H.S
∴ cotθ + tanθ = cosecθ × secθ
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