मराठी

Tan–1(x2 + y2) = a

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प्रश्न

tan–1(x2 + y2) = a

बेरीज
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उत्तर

Given that: tan–1(x2 + y2) = a

⇒ x2 + y2 = tan a.

Differentiating both sides w.r.t. x.

`"d"/"dx"(x^2 + y^2) = "d"/"dx"(tan "a")`

⇒ `2x + 2y * "dy"/"dx"` = 0

⇒ `2y * "dy"/"dx"` = – 2x

⇒ `"dy"/"dx" = (-2x)/(2y) = (-x)/y`

Hence, `"dy"/"dx" = (-x)/y`.

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पाठ 5: Continuity And Differentiability - Exercise [पृष्ठ १११]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 5 Continuity And Differentiability
Exercise | Q 56 | पृष्ठ १११

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