मराठी

Find the second order derivative of the function. sin (log x)

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प्रश्न

Find the second order derivative of the function.

sin (log x)

बेरीज
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उत्तर

Let, y = sin (log x)

Differentiating both sides with respect to x,

`dy/dx = d/dx sin (log x)`

= `cos (log x) d/dx log x`

= `cos (log x) * 1/x`

= `(cos (log x))/x`

Differentiating both sides again with respect to x,

`d/dx [dy/dx] = d/dx [(cos (log x))/x]`

`(d^2y)/dx^2 = (x d/dx cos (log x) - cos (log x) d/dx (x))/x^2`

= `(x [-sin (log x)] * 1/x - cos (log x * 1))/x^2`

= `(-[sin (log x) + cos (log x)])/x^2`

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पाठ 5: Continuity and Differentiability - Exercise 5.7 [पृष्ठ १८३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 5 Continuity and Differentiability
Exercise 5.7 | Q 10 | पृष्ठ १८३

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