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Find d2ydx2, if y = x - Mathematics and Statistics

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प्रश्न

Find `("d"^2"y")/"dx"^2`, if y = `sqrt"x"`

बेरीज
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उत्तर

y = `sqrt"x"`

Differentiating both sides w.r.t.x, we get

`"dy"/"dx" = 1/(2sqrt"x")`

∴ `"dy"/"dx" = 1/2 "x"^(-1/2)`

Again, differentiating both sides w.r.t. x , we get

`("d"^2"y")/"dx"^2 = 1/2 * "d"/"dx"("x"^(-1/2))`

`= 1/2 (- 1/2)* "x"^(- 3/2)`

∴ `("d"^2"y")/"dx"^2 = (-1)/4 "x"^(-3/2)`

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पाठ 3: Differentiation - EXERCISE 3.6 [पृष्ठ ९८]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 3 Differentiation
EXERCISE 3.6 | Q 1. 1) | पृष्ठ ९८

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