मराठी

Specific heat capacity of substance A is 3.8 J g^-1K^-1 whereas the  specific heat capacity of substance B is 0.4 J g^-1 K^-1

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प्रश्न

Specific heat capacity of substance A is 3.8 J g-1K-1 whereas the  specific heat capacity of substance B is 0.4 J g-1 K-1
(i) Which of the two is a good conductor of heat?
(ii) How is one led to the above conclusion?
(iii) If substances A and B are liquids then which one would be more useful in car radiators?

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उत्तर

(i) Substance B is a good conductor out of the two substances.

(ii) The specific heat capacity of B is lower than A. This means that less heat is required to raise the temperature of 1 g of B by 1 K than the heat required for A.

(iii) If both substances were liquids, then substance A will be more useful in radiators. This is because A will extract more heat without much change in its temperature as it has high specific heat capacity.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2013-2014 (March) Science Paper 1

संबंधित प्रश्‍न

A liquid X has the maximum specific heat capacity and is used as a coolant in Car Radiators. Name the liquid X.


State the effect of enhancement of green house effect.


Define specific heat. Is it same as heat capacity?

The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate Specific heat capacity of lead.


A. hot solid of mass 60 g at 100°C is placed in 150 g of water at 20° C. The final steady temperature recorded is 25°C. Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 J kg-1 °C-1]


Derive an expression for finding out the specific heat capacity of a body (solid) from the readings of an experiment given below:

(i) Mass of empty calorimeter (with stirrer) = m1 gm

(ii) Mass of the metal piece = M gm

(iii) Mass of colorimeter and water = m2 gm

(iv) Initial temperature and water = t1°C

(v) Temperature of hot solid (metal piece) = t2 °C

(vi) Final temperature of the mixture = t°C

(vii) Specific heat of calorimeter = 0.4 J gm / °C


Solve the following problem.

Specific latent heat of vaporization of water is 2.26 × 106 J/kg. Calculate the energy needed to change 5.0 g of water into steam at 100 ºC.


Read the passage and answer the questions based on it.

If heat is exchanged between a hot and cold object, the temperature of the cold object goes on increasing due to gain of energy and the temperature of the hot object goes on decreasing due to loss of energy. The change in temperature continues till the temperatures of both objects attain the same value. In this process, the cold object gains heat energy and the hot object loses heat energy. If the system of both the objects is isolated from the environment by keeping it inside a heat-resistant box then no energy can flow from inside the box or come into the box. In this situation, we get the following principle.
Heat energy lost by the hot object = Heat energy gained by the cold object. This is called the ‘Principle of heat exchange’.

  1. Where does heat transfer take place?
  2. In such a situation which principle of heat do you perceive?
  3. How can this principle be explained in short?
  4. Measuring the property of which substance this principle is used?

A block of ice of mass 120 g at temperature 0°C is put in 300 gm of water at 25°C. The xg of ice melts as the temperature of the water reaches 0°C. The value of x is ______.

[Use: Specific heat capacity of water = 4200 Jkg-1K-1, Latent heat of ice = 3.5 × 105 Jkg-1]


Which method is used to determine the specific heat capacity of both solids and liquids by mixing a substance of unknown specific heat with water?


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