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प्रश्न
Solve the following equation: `|(x + 2, x + 6, x - 1),(x + 6, x - 1,x + 2),(x - 1, x + 2, x + 6)|` = 0
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उत्तर
`|(x + 2, x + 6, x - 1),(x + 6, x - 1,x + 2),(x - 1, x + 2, x + 6)|` = 0
Applying R2 → R2 – R1 and R3 → R3 – R1, we get
`|(x + 2, x + 6, x - 1),(4, -7, 3),(-3, -4, 7)|` = 0
∴ (x + 2)( – 49 + 12) – (x + 6)(28 + 9) + (x – 1) ( – 16 – 21) = 0
∴ (x + 2) ( – 37) – (x + 6) (37) + (x – 1) (– 37) = 0
∴ – 37(x + 2 + x + 6 x + x – 1) = 0
∴ 3x + 7 = 0
∴ x = `(-7)/3`
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