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Solve the following equation: |x+2x+6x-1x+6x-1x+2x-1x+2x+6| = 0

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प्रश्न

Solve the following equation: `|(x + 2, x + 6, x - 1),(x + 6, x - 1,x + 2),(x - 1, x + 2, x + 6)|` =  0

योग
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उत्तर

`|(x + 2, x + 6, x - 1),(x + 6, x - 1,x + 2),(x - 1, x + 2, x + 6)|` =  0

Applying R2 → R2 – R1 and R3 → R3 – R1, we get

`|(x + 2, x + 6, x - 1),(4, -7, 3),(-3, -4, 7)|` = 0

∴ (x + 2)( – 49 + 12) – (x + 6)(28 + 9) + (x – 1) ( – 16 – 21) = 0
∴ (x + 2) ( – 37) – (x +  6) (37) + (x – 1) (– 37) = 0
∴ – 37(x + 2 + x + 6 x + x – 1) = 0
∴ 3x + 7 = 0

 ∴ x = `(-7)/3`

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अध्याय 6: Determinants - EXERCISE 6.2 [पृष्ठ ८९]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
अध्याय 6 Determinants
EXERCISE 6.2 | Q 3) | पृष्ठ ८९

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