मराठी

Without expanding evaluate the following determinant: abcbcacab|1ab+c1bc+a1ca+b|

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प्रश्न

Without expanding evaluate the following determinant:

`|(1, "a", "b" + "c"),(1, "b", "c" + "a"),(1, "c", "a" + "b")|`

बेरीज
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उत्तर

Let D = `|(1, "a", "b" + "c"),(1, "b", "c" + "a"),(1, "c", "a" + "b")|`

Applying C3 → C3 + C2, we get

D = `|(1, "a", "a" + "b" + "c"),(1, "b", "a" + "b" + "c"),(1, "c", "a" + "b" + "c")|`

Taking (a + b + c) common from C3, we get

D = `("a" + "b" + "c")|(1, "a", 1),(1, "b", 1),(1, "c", 1)|`

∴ D = (a + b + c)(0)   ...[∵ C1 and C3 are identical]

∴ D = 0

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पाठ 6: Determinants - EXERCISE 6.2 [पृष्ठ ८९]

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