Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`(x + 1)/(x - 1) + (x - 2)/(x + 2)` = 3
Advertisements
उत्तर
`(x + 1)/(x - 1) + (x - 2)/(x + 2)` = 3
⇒ `((x + 1)(x + 2)+ (x - 2)(x -1))/((x - 1)(x + 2)` = 3
⇒ `(x^2 + 2x + x + 2 + x^2 - x - 2x + 2)/(x^2 + 2x - x - 2)`
⇒ `(x^2 + 3x + 2 + x^2 - 3x + 2)/(x^2 + x - 2) = (3)/(1)`
⇒ 2x2 + 4 = 3x2 + 3x - 6
⇒ 2x2 + 4 - 3x2 - 3x + 6 = 0
⇒ -x2 - 3x + 10 = 0
⇒ x2 + 3x - 10 = 0
⇒ x2 + 5x - 2x - 10 = 0
⇒ x(x + 5) - 2(x + 5) = 0
⇒ (x + 5) (x - 2) = 0
Either x + 5 = 0,
then x = -5
or
x - 2 = 0,
then x = 2
Hence x = -5, 2.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
x2 - x - a(a + 1) = 0
Two number differ by 4 and their product is 192. Find the numbers?
`2x^2+5x-3=0`
Solve the following equation: 4x2 + 4 bx - (a2 - b2) = 0
Solve the following equation : `"x"^2 - 4 sqrt 2 "x" + 6 = 0 `
Solve the following equation:
`("x" + 1)/("x" - 1) - ("x" - 1)/("x" + 1) = 5/6 , "x" ≠ -1,1`
If `sqrt (2/3)` is a solution of equation 3x2 + mx + 2 = 0, find the value of m.
Car A travels x km for every litre of petrol, while car B travels (x + 5) km for every litre of petrol.
If car A use 4 litre of petrol more than car B in covering the 400 km, write down and equation in x and solve it to determine the number of litre of petrol used by car B for the journey.
Solve the following equation by factorization
2x2 – 9x + 10 = 0,when x∈N
Solve the following equation by factorisation :
x(x + 1) + (x + 2)(x + 3) = 42
