Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`(1)/(x - 3) - (1)/(x + 5) = (1)/(6)`
Advertisements
उत्तर
`(1)/(x - 3) - (1)/(x + 5) = (1)/(6)`
`(x + 5 - x + 3)/((x - 3) (x + 5)) = (1)/(6)`
⇒ `(8)/(x^2 + 2x - 15) = (1)/(6)`
⇒ x2 + 2x - 15 = 48
⇒ x2 + 2x - 15 - 48 = 0
⇒ x2 + 2x - 63 = 0
⇒ x2 + 9x - 7x - 63 = 0
⇒ x(x + 9) - 7(x + 9) = 0
⇒ (x + 9) (x - 7) = 0
Either x + 9 = 0,
then x = -9
or
x - 7 = 0,
then x = 7
Hence x = -9, 7.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`10x-1/x=3`
The sum of two natural numbers is 9 and the sum of their reciprocals is `1/2`. Find the numbers.
Find the value of k for which the following equations have real and equal roots:
\[x^2 - 2\left( k + 1 \right)x + k^2 = 0\]
Solve the following equation:
(2x+3) (3x-7) = 0
Solve the following equation :
`1/(("x" - 1)(x - 2)) + 1/(("x" - 2)("x" - 3)) + 1/(("x" - 3)("x" -4)) = 1/6`
The length of the sides forming a right angle in a triangle are 5x cm and (3x-1) cm. If the area of the triangle is 60cm2, find the hypotenuse.
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
In each of the following determine whether the given values are solutions of the equation or not.
3x2 - 2x - 1 = 0; x = 1
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
If the area of a square is 400 m2, then find the side of the square by the method of factorization.
