Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`3x - (8)/x `= 2
Advertisements
उत्तर
`3x - (8)/x `= 2
`(3x^2 - 8)/x` = 2
⇒ 3x2 - 8 = 2x
⇒ 3x2 - 2x - 8 = 0
⇒ 3x2 - 6x + 4x - 8 = 0
⇒ 3x(x - 2) + 4(x - 2) = 0
⇒ (x - 2)(3x + 4) = 0
Either x - 2 = 0,
then x = 2
or
3x + 4 = 0,
then 3x = -4
⇒ x = `(-4)/(3)`
Hence x = 2, `(-4)/(3)`.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`(2x – 3)^2 = 49`
`7x^2+3x-4=0`
The sum of two natural numbers is 9 and the sum of their reciprocals is `1/2`. Find the numbers .
Solve for x: `3x^2-2sqrt3x+2=0`
Solve the following quadratic equations by factorization:
\[3\left( \frac{7x + 1}{5x - 3} \right) - 4\left( \frac{5x - 3}{7x + 1} \right) = 11; x \neq \frac{3}{5}, - \frac{1}{7}\]
If a and b are roots of the equation x2 + ax + b = 0, then a + b =
Solve the following quadratic equation by factorisation:
9x2 - 3x - 2 = 0
Solve the following equation by factorization
3x2 – 5x – 12 = 0
If x = p is a solution of the equation x(2x + 5) = 3, then find the value of p.
Find the roots of the following quadratic equation by the factorisation method:
`3sqrt(2)x^2 - 5x - sqrt(2) = 0`
