Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`(x + 2)/(x + 3) = (2x - 3)/(3x - 7)`
Advertisements
उत्तर
`(x + 2)/(x + 3) = (2x - 3)/(3x - 7)`
(x + 2) (3x - 7) = (2x - 3) (x + 3)
⇒ 3x2 - 7x + 6x - 14 = 2x2 + 6x - 3x - 9
⇒ 3x2 - x - 14 = 2x2 + 3x - 9
⇒ 3x2 - x - 14 - 2x2 - 3x + 9 =0
⇒ x2 - 4x - 5 = 0
⇒ x2 - 5x + x - 5 = 0
x(x - 5) + 1(x - 5) = 0
⇒ (x - 5) (x + 1) = 0
Either x - 5 = 0,
then x = 5
or
x + 1 = 0,
then x = -1
Hence x = 5, -1.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
Find the roots of the following quadratic equation by factorisation:
`sqrt2 x^2 +7x+ 5sqrt2 = 0`
A piece of cloth costs Rs. 35. If the piece were 4 m longer and each meter costs Rs. 1 less, the cost would remain unchanged. How long is the piece?
Solve the given quadratic equation for x : 9x2 – 9(a + b)x + (2a2 + 5ab + 2b2) = 0 ?
In each of the following, determine whether the given values are solution of the given equation or not:
`x = 1/x = (13)/(6), x = (5)/(6), x = (4)/(3)`
Solve the following equation by factorization
x2 – 3x – 10 = 0
Solve the following equation by factorization.
a2x2 + 2ax + 1 = 0, a ≠ 0
Solve the following equation by factorization
`x/(x + 1) + (x + 1)/x = (34)/(15)`
Solve the following equation by factorisation :
`(6)/x - (2)/(x - 1) = (1)/(x - 2)`
Using quadratic formula find the value of x.
p2x2 + (p2 – q2)x – q2 = 0
