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प्रश्न
Solve the following equation by factorization.
a2x2 + 2ax + 1 = 0, a ≠ 0
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उत्तर
a2x2 + 2ax + 1 = 0
⇒ a2x2 + ax + ax + 1 = 0
⇒ ax(ax + 1) +1 (ax + 1) = 0
⇒ ax(ax + 1) (ax + 1) = 0
⇒ (ax + 1)2 = 0
∴ ax + 1 = 0 or ax + 1 = 0
⇒ `x = -(1)/a or x = -(1)/a`
Hence x = `-(1)/a "or" x = -(1)/a`.
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