Question

Solve the following equation by factorization 

x² – (p + q)x + pq = 0

Answer 1

 x² – (p + q)x + pq = 0
x² - px - qx + pq = 0
x(x - p) -q)x - p) = 0
⇒ (x - p) (x - q) = 0
Either x - p = 0,
then x = p
or 
x - q = 0,
then x = q
Hence x = p, q.