Advertisements
Advertisements
प्रश्न
Sketch and describe the locus of the vertices of all triangles with a given base and a given altitude.
Advertisements
उत्तर
Steps of construction:
Draw a line XY parallel to the base BC from the vertex A.

This line is the locus of vertex A. All the triangles which have the base BC and length of altitude equal to AD.
APPEARS IN
संबंधित प्रश्न
Construct a triangle ABC, in which AB = 4.2 cm, BC = 6.3 cm and AC = 5 cm. Draw perpendicular bisector of BC which meets AC at point D. Prove that D is equidistant from B and C.
In each of the given figures; PA = PB and QA = QB.
| i. | ![]() |
| ii. | ![]() |
Prove, in each case, that PQ (produce, if required) is perpendicular bisector of AB. Hence, state the locus of the points equidistant from two given fixed points.
In the figure given below, find a point P on CD equidistant from points A and B.

In the given triangle ABC, find a point P equidistant from AB and AC; and also equidistant from B and C.
Describe the locus of a stone dropped from the top of a tower.
Describe the locus of the door handle, as the door opens.
Describe the locus of points inside a circle and equidistant from two fixed points on the circumference of the circle.
By actual drawing obtain the points equidistant from lines m and n; and 6 cm from a point P, where P is 2 cm above m, m is parallel to n and m is 6 cm above n.
In Δ ABC, the perpendicular bisector of AB and AC meet at 0. Prove that O is equidistant from the three vertices. Also, prove that if M is the mid-point of BC then OM meets BC at right angles.
ΔPBC and ΔQBC are two isosceles triangles on the same base BC but on the opposite sides of line BC. Show that PQ bisects BC at right angles.


