Advertisements
Advertisements
प्रश्न
Simplify by rationalising the denominator in the following.
`(2)/(3 + sqrt(7)`
Advertisements
उत्तर
`(2)/(3 + sqrt(7)`
= `(2)/(3 + sqrt(7)) xx (3 - sqrt(7))/(3 - sqrt(7)`
= `(2(3 - sqrt(7)))/((3)^2 - (sqrt(7))^2)`
= `(2(3 - sqrt(7)))/(9 - 7)`
= `(2(3 - sqrt(7)))/(2)`
= 3 - `sqrt(7)`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`1/(sqrt 3 - sqrt 2)`
Simplify by rationalising the denominator in the following.
`(3sqrt(2))/sqrt(5)`
Simplify by rationalising the denominator in the following.
`(1)/(5 + sqrt(2))`
Simplify the following
`(4 + sqrt(5))/(4 - sqrt(5)) + (4 - sqrt(5))/(4 + sqrt(5)`
Simplify the following :
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2)`
If `(sqrt(2.5) - sqrt(0.75))/(sqrt(2.5) + sqrt(0.75)) = "p" + "q"sqrt(30)`, find the values of p and q.
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of
x2 - y2 + xy
Simplify:
`(sqrt(x^2 + y^2) - y)/(x - sqrt(x^2 - y^2)) ÷ (sqrt(x^2 - y^2) + x)/(sqrt(x^2 + y^2) + y)`
Draw a line segment of length `sqrt8` cm.
Using the following figure, show that BD = `sqrtx`.
