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प्रश्न
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
CH3 – Br + KOH →
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उत्तर
\[\ce{CH3 – Br + KOH →}\]
\[\ce{CH3 – Br + KQH → CH3OH + KBr}\]
Nucleophile is: OH–
APPEARS IN
संबंधित प्रश्न
For the following reactions
- \[\ce{CH3CH2CH2Br + KOH → CH3 – CH = CH2 + KBr + H2O}\]
- \[\ce{(CH3)3CBr + KOH → (CH3)3COH + KBr}\]
Which of the following statement is correct?
What is the hybridisation state of benzyl carbonium ion?
Which of the following species is not electrophilic in nature?
Which of the group has highest + I effect?
Which of the following species does not exert a resonance effect?
Assertion: Tertiary Carbocations are generally formed more easily than primary Carbocations ions.
Reason: Hyper conjucation as well as inductive effect due to additional alkyl group stabilize tertiary carbonium ions.
Heterolytic fission of C–C bond results in the formation of ______.
Which of the following represent a set of nucleophiles?
What is electrophiles? Give a suitable example.
Give example for the following type of organic reaction.
β - elimination
