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प्रश्न
Write a short note on hyperconjucation.
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उत्तर
The delocalisation of electrons of a bond is called as hyperconjugation. It is a special stabilising effect that results due to the interaction of electrons of a σ -bond (usually C – H or C – C) with the adjacent, empty non-bonding p-orbital or an anti¬bonding σ* or π*-orbitals resulting in an extended molecular orbital. Unlike the electromeric effect, hyper conjugation is a permanent effect.
It requires an α-CH group or a lone pair on atom-like N, O adjacent to a π bond (sp2 hybrid carbon). It occurs by the overlapping of the σ-bonding orbital or the orbital containing a lone pair with the adjacent π-orbital or p-orbital.
Example:
In propene, the σ -electrons of C-H bond of methyl group can be delocalised into the π -orbital of doubly bonded carbonas represented below.

No bond resonance structures shown by propene are due to hyperconjugation
In the above structure, the sigma bond is involved in resonance and breaks in order to supply electrons for delocalization giving rise to 3 new canonical forms. In the contributing canonical structures: (Il), (III) & (IV) of propene, there is no bond between an α-carbon and one of the hydrogen atoms. Hence the hyperconjugation is also known as “no bond resonance” or “Baker Nathan effect”. The structures (II), (III) & (IV) are polar in nature.
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संबंधित प्रश्न
Homolytic fission of covalent bond leads to the formation of ______.
Which of the following species does not exert a resonance effect?
Assertion: Tertiary Carbocations are generally formed more easily than primary Carbocations ions.
Reason: Hyper conjucation as well as inductive effect due to additional alkyl group stabilize tertiary carbonium ions.
Heterolytic fission of C–C bond results in the formation of ______.
Which of the following represent a set of nucleophiles?
The geometrical shape of carbocation is ______.
Write a short note on resonance.
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
CH3 – Br + KOH →
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
\[\ce{CH3 – O – CH3 + HI →}\]
Explain inductive effect with suitable example.
