Advertisements
Advertisements
प्रश्न
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
CH3 – Br + KOH →
Advertisements
उत्तर
\[\ce{CH3 – Br + KOH →}\]
\[\ce{CH3 – Br + KQH → CH3OH + KBr}\]
Nucleophile is: OH–
APPEARS IN
संबंधित प्रश्न
For the following reactions
- \[\ce{CH3CH2CH2Br + KOH → CH3 – CH = CH2 + KBr + H2O}\]
- \[\ce{(CH3)3CBr + KOH → (CH3)3COH + KBr}\]
Which of the following statement is correct?
What is the hybridisation state of benzyl carbonium ion?
Which of the following species is not electrophilic in nature?
Homolytic fission of covalent bond leads to the formation of ______.
Which of the group has highest + I effect?
Which of the following species does not exert a resonance effect?
Assertion: Tertiary Carbocations are generally formed more easily than primary Carbocations ions.
Reason: Hyper conjucation as well as inductive effect due to additional alkyl group stabilize tertiary carbonium ions.
Which of the following species does not acts as a nucleophile?
Write a short note on resonance.
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
\[\ce{CH3 – O – CH3 + HI →}\]
