Advertisements
Advertisements
प्रश्न
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
\[\ce{CH3 – O – CH3 + HI →}\]
Advertisements
उत्तर
\[\ce{CH3 – O – CH3 + HI →}\]
\[\ce{CH3 – O – CH3 + HI → CH3OH + CH3 I
}\]
Nucleophile is: I–
APPEARS IN
संबंधित प्रश्न
What is the hybridisation state of benzyl carbonium ion?
Decreasing order of nucleophilicity is ______.
Homolytic fission of covalent bond leads to the formation of ______.
Hyper Conjugation is also known as
Which of the group has highest + I effect?
Which of the following species does not exert a resonance effect?
- I effect is shown by ______.
Which of the following carbocation will be most stable?
Assertion: Tertiary Carbocations are generally formed more easily than primary Carbocations ions.
Reason: Hyper conjucation as well as inductive effect due to additional alkyl group stabilize tertiary carbonium ions.
What is electrophiles? Give a suitable example.
