Advertisements
Advertisements
प्रश्न
For the following reactions
- \[\ce{CH3CH2CH2Br + KOH → CH3 – CH = CH2 + KBr + H2O}\]
- \[\ce{(CH3)3CBr + KOH → (CH3)3COH + KBr}\]
Which of the following statement is correct?
पर्याय
(A) is elimination, (B) and (C) are substitution
(A) is substitution, (B) and (C) are elimination
(A) and (B) are elimination and (C) is addition reaction
(A) is elimination, B is substitution and (C) is addition reaction.
Advertisements
उत्तर
(A) is elimination, B is substitution and (C) is addition reaction.
APPEARS IN
संबंधित प्रश्न
Decreasing order of nucleophilicity is ______.
Homolytic fission of covalent bond leads to the formation of ______.
Which of the group has highest + I effect?
- I effect is shown by ______.
Assertion: Tertiary Carbocations are generally formed more easily than primary Carbocations ions.
Reason: Hyper conjucation as well as inductive effect due to additional alkyl group stabilize tertiary carbonium ions.
Write a short note on resonance.
Write a short note on hyperconjucation.
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
CH3 – Br + KOH →
Show the heterolysis of a covalent bond by using curved arrow notation and complete the following equation. Identify the nucelophile.
\[\ce{CH3 – O – CH3 + HI →}\]
Give example for the following type of organic reaction.
β - elimination
