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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Show that for a Wave Travelling on a String Y M a X ν M a X = ν M a X α M a X , Where the Symbols Have Usual Meanings. Can We Use Componendo and Dividendo Taught in Algebra to Write - Physics

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प्रश्न

Show that for a wave travelling on a string 
\[\frac{y_{max}}{\nu_{max}} = \frac{\nu_{max}}{\alpha_{max}},\]

where the symbols have usual meanings. Can we use componendo and dividendo taught in algebra to write
\[\frac{y_{max} + \nu_{max}}{\nu_{max} - \nu_{max}} = \frac{\nu_{max} + \alpha_{max}}{\nu_{max} - \alpha_{max}}?\]

बेरीज
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उत्तर

\[\frac{y_\max}{v_\max} = \frac{v_\max}{a_\max}\] 

\[y = A\sin\left( \omega t - kx \right)\] 

\[v = \frac{dy}{dt} = A\cos\left( \omega t - kx \right)\] 

\[ v_\max  = A\omega\] 

\[a = \frac{dv}{dt} =  - A \omega^2 \sin\left( \omega t - kx \right)\] 

\[ a_\max  =  \omega^2 A\]
To prove,

\[\frac{y_\max}{v_\max} = \frac{v_\max}{a_\max}\] 

\[LHS\] 

\[\frac{y_\max}{v_\max} = \frac{A}{A\omega} = \frac{1}{\omega}\] 

\[RHS\] 

\[\frac{v_\max}{a_\max} = \frac{A\omega}{\omega^2 A} = \frac{1}{\omega}\]
No, componendo and dividendo is not applicable. We cannot add quantities of different dimensions.

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The Speed of a Travelling Wave
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पाठ 15: Wave Motion and Waves on a String - Short Answers [पृष्ठ ३२१]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 15 Wave Motion and Waves on a String
Short Answers | Q 6 | पृष्ठ ३२१

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