मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Use the formula v=γPρ to explain why the speed of sound in air increases with temperature.

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प्रश्न

Use the formula `v = sqrt((gamma P)/rho)` to explain why the speed of sound in air increases with temperature.

संख्यात्मक
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उत्तर १

Take the relation:

`v = sqrt((gammaP)/rho)`      ...(i)

For one mole of an ideal gas, the gas equation can be written as:

PV = RT

`"P" = ("RT")/"V"`  .....(ii)

Substituting equation (ii) in equation (i), we get:

`"v" = sqrt((gamma"RT")/("V"rho)) = sqrt((gamma"RT")/"M")`  ....(iv)

Where,

Mass, M = ρV is a constant

γ and R are also constants

We conclude from equation (iv) that `v prop sqrt"T"`.

Hence, the speed of sound in a gas is directly proportional to the square root of the temperature of the gaseous medium, i.e., the speed of the sound increases with an increase in the temperature of the gaseous medium and vice versa.

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उत्तर २

We are given that `v = sqrt((gamma p)/rho)`

We know PV = nRT            (For n moles of ideal gas)

`=> "PV" = "m"/"M" "RT"`

where m is the total mass and M is the molecular mass of the gas

`:. "P" = "m"/"M" * "RT"/M`

`= (rho"RT")/"M"`

`=> "P"/rho =  "RT"/"M"`

Since `"P"/rho = "RT"/"M"`, therefore,  `v = sqrt((gamma "P")/rho)`

=  `sqrt((gamma "RT")/"M")`

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पाठ 14: Waves - Exercises [पृष्ठ ३८७]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 11
पाठ 14 Waves
Exercises | Q 4.2 | पृष्ठ ३८७

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