मराठी

Show that the Locus of the Centres of All Circles Passing Through Two Given Points a and B, is the Perpendicular Bisector of the Line Segment Ab. - Mathematics

Advertisements
Advertisements

प्रश्न

Show that the locus of the centres of all circles passing through two given points A and B, is the perpendicular bisector of the line segment AB.

बेरीज
Advertisements

उत्तर

Let  P and Q be the centres of two circles S and S', each passing through two given points A and B. Then,
PA = PB    ...[Radii of the same circle]
⇒ P lies on the perpendicular bisector of AB  ...(i)
Again, QA = QB    ...[Radii of the same circle]
⇒ Q lies on the perpendicular bisector of AB  ...(ii)

From (i) and (ii), it follows that P and Q both lies on the perpendicular bisector of AB.
Hence, the locus of the centres of all the circles passing through A and B is the perpendicular bisector of AB.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Use ruler and compasses only for this question.

  1. Construct ΔABC, where AB = 3.5 cm, BC = 6 cm and ∠ABC = 60°.
  2. Construct the locus of points inside the triangle which are equidistant from BA and BC.
  3. Construct the locus of points inside the triangle which are equidistant from B and C.
  4. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.

Draw an ∠ABC = 60°, having AB = 4.6 cm and BC = 5 cm. Find a point P equidistant from AB and BC; and also equidistant from A and B. 


In the figure given below, find a point P on CD equidistant from points A and B. 


In the given triangle ABC, find a point P equidistant from AB and AC; and also equidistant from B and C. 

 


Describe the locus of the centre of a wheel of a bicycle going straight along a level road.


Describe the locus of points at distances less than 3 cm from a given point.


A straight line AB is 8 cm long. Draw and describe the locus of a point which is:

  1. always 4 cm from the line AB.
  2. equidistant from A and B.
    Mark the two points X and Y, which are 4 cm from AB and equidistant from A and B. Describe the figure AXBY.

Draw a triangle ABC in which AB = 6 cm, BC = 4.5 cm and AC = 5 cm. Draw and label:

  1. the locus of the centres of all circles which touch AB and AC,
  2. the locus of the centres of all the circles of radius 2 cm which touch AB.
    Hence, construct the circle of radius 2 cm which touches AB and AC . 

In  Δ ABC, the perpendicular bisector of AB and AC meet at 0. Prove that O is equidistant from the three vertices. Also, prove that if M is the mid-point of BC then OM meets BC at right angles. 


ΔPBC and ΔQBC are two isosceles triangles on the same base BC but on the opposite sides of line BC. Show that PQ bisects BC at right angles.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×